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		<title>Half Adder and Full Adder Explained</title>
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		<pubDate>Mon, 14 Feb 2022 17:43:54 +0000</pubDate>
				<category><![CDATA[Digital Electronics]]></category>
		<category><![CDATA[full adder logic circuit]]></category>
		<category><![CDATA[full adder truth table]]></category>
		<category><![CDATA[full adder using half adder]]></category>
		<category><![CDATA[half adder and full adder]]></category>
		<category><![CDATA[half adder logic circuit]]></category>
		<category><![CDATA[half adder truth table]]></category>
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					<description><![CDATA[<p>In this article, the logic circuit, the truth table, and the working of half adder and full adder are explained. Half Adder The half adder is the logic circuit that adds the two bits and generates the sum bit (S) and carry bit (C) as an output. The truth table of the half adder is ... <a title="Half Adder and Full Adder Explained" class="read-more" href="https://www.allaboutelectronics.org/half-adder-and-full-adder-explained/">Read more<span class="screen-reader-text">Half Adder and Full Adder Explained</span></a></p>
<p>The post <a href="https://www.allaboutelectronics.org/half-adder-and-full-adder-explained/">Half Adder and Full Adder Explained</a> appeared first on <a href="https://www.allaboutelectronics.org">ALL ABOUT ELECTRONICS</a>.</p>
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<p>In this article, the logic circuit, the truth table, and the working of half adder and full adder are explained. </p>



<h2 class="has-text-color wp-block-heading" id="half-adder" style="color:#0f3698"><strong>Half Adder</strong></h2>



<p>The half adder is the logic circuit that adds the two bits and generates the sum bit (S) and carry bit (C) as an output. The truth table of the half adder is shown below.</p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_2.png"><img fetchpriority="high" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_2.png" alt="" class="wp-image-1768" width="403" height="165" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_2.png 616w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_2-300x123.png 300w" sizes="(max-width: 403px) 100vw, 403px" /></a></figure></div>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_3.png"><img decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_3.png" alt="" class="wp-image-1763" width="317" height="234" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_3.png 479w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_3-300x222.png 300w" sizes="(max-width: 317px) 100vw, 317px" /></a><figcaption><strong>Truth Table of Half Adder</strong></figcaption></figure></div>



<p>As per the truth table, the sum output is 1 for two input combinations. That means when A is 1 and B is 0 OR A is 0 and B is 1. </p>



<p>Algebraically, <strong>S = A&#8217; B + A B&#8217; = A ⊕ B</strong></p>



<p>Likewise, the carry output is logic &#8216;1&#8217; only for one input combination (when A = 1 and B = 1). </p>



<p>If we denote the carry output as C, then <strong>C = AB</strong></p>



<p>Figure. 1 shows the Boolean expression and the logic circuit of the half adder.</p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_4.png"><img decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_4.png" alt="" class="wp-image-1764" width="298" height="134" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_4.png 431w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_4-300x135.png 300w" sizes="(max-width: 298px) 100vw, 298px" /></a></figure></div>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_5.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_5.png" alt="" class="wp-image-1765" width="290" height="266" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_5.png 467w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_5-300x276.png 300w" sizes="(max-width: 290px) 100vw, 290px" /></a></figure></div>



<p class="has-text-align-center"><strong>Fig. 1 The Boolean expressions and the logic circuit of the Half Adder</strong></p>



<p class="has-text-align-justify">The half adder circuit is suitable for the addition of two bits at the LSB (Least Significant Bit) position. Because during the addition of two bits at the LSB position, there is no incoming carry. But whenever there is an incoming carry (C<sub>in</sub>) along with the two bits, then a full adder circuit can be used. </p>



<h2 class="has-text-color wp-block-heading" id="full-adder" style="color:#0f3698"><strong>Full Adder</strong></h2>



<p>The full adder is the combinational circuit that adds the two bits along with the incoming carry (C<sub>in</sub>) and generates the sum bit (S)  and an outgoing carry bit (C<sub>out</sub>) as an output. The truth table of the full adder is shown below.</p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_6.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_6.png" alt="" class="wp-image-1769" width="500" height="207" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_6.png 706w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_6-300x124.png 300w" sizes="(max-width: 500px) 100vw, 500px" /></a></figure></div>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_7.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_7.png" alt="" class="wp-image-1770" width="372" height="403" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_7.png 571w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_7-277x300.png 277w" sizes="(max-width: 372px) 100vw, 372px" /></a><figcaption><strong>The Truth table of the Full Adder</strong></figcaption></figure></div>



<p>As per the truth table of the full-adder, the sum and carry outputs are logic &#8216;1&#8217; for 4 different input combinations. So, let&#8217;s find the simplified algebraic expression of sum (S) and carry (C<sub>out</sub>) </p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_8.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_8.png" alt="" class="wp-image-1771" width="401" height="252" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_8.png 635w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_8-300x189.png 300w" sizes="(max-width: 401px) 100vw, 401px" /></a></figure></div>



<p>Similarly, using the K-map, it is possible to find the simplified boolean expression for the carry output. The K-map for the carry output of the full adder is shown below.</p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_12.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_12.png" alt="" class="wp-image-1772" width="553" height="285" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_12.png 943w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_12-300x155.png 300w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_12-768x397.png 768w" sizes="(max-width: 553px) 100vw, 553px" /></a></figure></div>



<p>After the simplification, the carry output <strong>C<sub>out </sub>= AB + B C<sub>in</sub> + AC<sub>in</sub></strong></p>



<p>Moreover, the carry output can also be written as follows:</p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_9.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_9.png" alt="" class="wp-image-1774" width="469" height="316" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_9.png 717w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_9-300x202.png 300w" sizes="(max-width: 469px) 100vw, 469px" /></a></figure></div>



<p>Based on these Boolean expressions, the logic circuit for the sum (S) and the carry (C<sub>out</sub>) output is shown below. </p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_10.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_10.png" alt="" class="wp-image-1776" width="404" height="108" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_10.png 636w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_10-300x80.png 300w" sizes="(max-width: 404px) 100vw, 404px" /></a></figure></div>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_11.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_11.png" alt="" class="wp-image-1777" width="492" height="234" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_11.png 778w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_11-300x143.png 300w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/slide_11-768x365.png 768w" sizes="(max-width: 492px) 100vw, 492px" /></a></figure></div>



<p>As it can be seen from the logic circuit, we require 5 two-input gates and 1 three-input gate to implement the full adder. So, in total, we require 6 logic gates. But using another expression of C<sub>out</sub> <strong>(C<sub>out</sub> = AB + Cin ( A ⊕ B) )</strong>, we can reduce the total number of gates.</p>



<p>The same circuit is shown below. And if you closely observe then the circuit consist of two half-adders and one OR gate. </p>



<div class="wp-block-image"><figure class="aligncenter size-full is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_14.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_14.png" alt="" class="wp-image-1779" width="523" height="335" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_14.png 936w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_14-300x192.png 300w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_14-768x492.png 768w" sizes="(max-width: 523px) 100vw, 523px" /></a></figure></div>



<p>The same thing can also be shown in terms of the Half adder blocks. </p>



<div class="wp-block-image"><figure class="aligncenter size-large is-resized"><a href="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13.png"><img loading="lazy" decoding="async" src="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13-1024x348.png" alt="" class="wp-image-1780" width="604" height="205" srcset="https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13-1024x348.png 1024w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13-300x102.png 300w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13-768x261.png 768w, https://www.allaboutelectronics.org/wp-content/uploads/2022/02/Slide_13.png 1128w" sizes="(max-width: 604px) 100vw, 604px" /></a><figcaption><strong>Full Adder using Two Half Adders</strong></figcaption></figure></div>



<p>For more information, do check this video on Half Adder and Full Adder.</p>



<figure class="wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio"><div class="wp-block-embed__wrapper">
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